How do you simplify #1/2 (log_bM + log_bN - log_bP)#?
1 Answer
Jan 22, 2018
Explanation:
Since our bases are all equal we can use
#= 1/2log_b((MN)/P)#
We can now use
#= log_b((MN)/P)^(1/2)#
#= log_b sqrt((MN)/P)#
Hopefully this helps!