An object with a mass of 120g is dropped into 640mL of water at 0∘C. If the object cools by 36∘C and the water warms by 12∘C, what is the specific heat of the material that the object is made of?

1 Answer
Jane
Jan 23, 2018

1.77 Calorie gm^-1 'C^-1

Explanation:

To come in thermal equilibrium,heat energy released by the object is m×s×∂θ = 120×s×36 Calorie.(where,s is its specific heat)

And during this process,heat taken by water is 640×1×1×12 Calorie (Here,mass of water = volume×density)

So,equating both we get, s=1.77 Calorie gm^-1 'C^-1

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