How can we write #1.5555...........# (#5# repeating endlessly) as fraction?

2 Answers
Jan 24, 2018

#1.55555555555...=14/9=1 5/9#

Explanation:

Let #x=1.55555555555...# .........(1)

then #10x=15.55555555555...# .........(2)

Subtracting (1) from (2), we get

#10x-x-=15.55555555555...- 1.55555555555...=14#

i.e. #9x=14#

hence #x=14/9#

i.e. #1.55555555555...=14/9=1 5/9#

Jan 24, 2018

#1.bar5=x#.....(1)
#1.bar5 xx 10 =15.bar5=10x#.........(2)
Put equation 1 and 2
#10x-x=15.55555-1.55555#
#9x=14#
#x=14/9#
#x=1 5/9#