Question #5230c

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Answer 1 · 2018-01-25T15:04:18

7.2 #mu#m.

The photon energy #E_gamma# is related to the corresponding light wavelength #lambda# by

#E_gamma = (hc)/lambda#,

where #h# and #c# are the Planck's constant and the speed of light in vacuum, respectively.

In this case, #E_gamma = 2.754 * 10^20 J#, then:

#2.754 * 10^20 = (6.6 * 10^-34 * 3 * 10^8)/lambda#;

#lambda = (19.8 * 10^-26)/(2.754 * 10^20)#.

This yields, approximately:

#lambda = 7.2 * 10^-6 m#.