How do you graph #3x+4y=-10# using intercepts?

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Answer 1 · 2018-01-26T14:26:32

See a solution process below:

First, we will find the #x# intercept by solve the equation for #y = #:

#3x + (4 * 0) = -10#

#3x + 0 = -10#

#3x = -10#

#(3x)//color(red)(3) = -10/color(red)(3)#

#x = -10/3# or #(-10/3, 0)#

Next, we will find the #y# intercept by solve the equation for #x = #:

#(3 xx 0) + 4y = -10#

#0 + 4y = -10#

#4y = -10#

#(4y)//color(red)(4) = -10/color(red)(4)#

#y = -5/2# or #(0, -5/2)#

We can then plot the two intercepts on the coordinate plane:

graph{(x^2+(y+(5/2))^2-0.025)((x+(10/3))^2+y^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x + 4y + 10)(x^2+(y+(5/2))^2-0.025)((x+(10/3))^2+y^2-0.025)=0 [-10, 10, -5, 5]}