How do you identity if the equation #x^2=8y# is a parabola, circle, ellipse, or hyperbola and how do you graph it?

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Answer 1 · 2018-01-27T06:09:24

It is a parabola opening up with vertex at #(0, 0)#

Given -

#x^2=8y#

It is a parabola opening up.
The general form of the equation of a parabola opening up is -

#x^2=4ay#

Where -

#4# is a constant
#a# is the distance from the vertex to focus.
Its vertex is #(0,0)#

The given equation #x^2=8y# can be written as -

#x^2=4xx2xxy#

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