Question

Question #8284d

Answer 1

4.0 m/s

Explanation:

Use the kinematic equations or use the definitions of acceleration and velocity to derive the kinematic equation blow.

A) `Deltax= v_0t+1/2at^2`
`v_0= 0 larr`starting from rest, and the clock is reset to zero.

`t = sqrt((2Deltax)/a)= 4.0 hrs`

The answer is assuming that `a = (3km)/(hr^2` because the time unit is left blank in the question.

B.) Derive the equation from the de
`a = (dv)/dt and v= dx/dt`

Given the a = constant and initially `t=0, v(0)=v_0, x(0)=x_0`
From `a = (dv)/dt`, and take the antiderivative,
`int_(0)^tadt= v - v_0`

`rArrv= v_0 + at`
Because `v=(dx)/dt`
`rArr dx/dt= v_0 + at`
Take the antiderivative to get
`Deltax =v_0t + 1/2at^2`
which is just the kinematic equation used above.