What is the perimeter of parallelogram ABCD with vertices # A(-2, 2), B(4,2), C(-6,-1), and D(0,-1) #?

1 Answer
Shwetank Mauria
Jan 28, 2018

Perimeter is #22# units.

Explanation:

See the location of points in the graph shown below:

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Side #AB=sqrt((4-(-2))^2+(2-2)^2)=sqrt(36+0)=6#

and side #BD=sqrt((4-0)^2+(2-(-1))^2)=sqrt(16+9)=sqrt25=5#

Hence perimeter is #2xx(6+5)=22# units.

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