If $sin θ = - \frac{4}{5}$ $sin theta = -4/5$ and $θ$ $theta$ is in the fourth quadrant, find $cos θ$ $cos theta$ ?

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If $sin θ = - \frac{4}{5}$ $sin theta = -4/5$ and $θ$ $theta$ is in the fourth quadrant, find $cos θ$ $cos theta$ ?

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Answer 1 · 2018-02-02T04:06:49

${cos}^{2} t = 1 - {sin}^{2} t = 1 - \frac{16}{25} = \frac{9}{25}$ $cos^2 t = 1 - sin^2 t = 1 - 16/25 = 9/25$
$cos t = \pm \frac{3}{5}$ $cos t = +- 3/5$
Since t is in Quadrant 4, then, cos t is negative.
$cos t = - \frac{3}{5}$ $cos t = - 3/5$

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If $sin θ = - \frac{4}{5}$ $sin theta = -4/5$ and $θ$ $theta$ is in the fourth quadrant, find $cos θ$ $cos theta$ ?

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If $sin θ = - \frac{4}{5}$ $sin theta = -4/5$ and $θ$ $theta$ is in the fourth quadrant, find $cos θ$ $cos theta$ ?