What is the distance between the following polar coordinates?: (8,(-21pi)/12), (5,(-3pi)/8)

1 Answer
Feb 2, 2018

10.937

Explanation:

First (8,-(21pi)/12) can be simplified a bit (8, -(7pi)/4), and since -(7pi)/4 is coterminal to pi/4, we'll use (8,pi/4) as an equivalent point. The other point we'll keep as (5,-(3pi)/8).

If we plot the points and use them as two vertices of a triangle with the origin as the third vertex, we have sides 8 and 5 with an angle of pi/4 + (3pi)/8 = (5pi)/8 between them.

For this triangle we can use the Law of Cosines to find the side opposite (5pi)/8, which is the distance between the given points:

c=sqrt(a^2+b^2-2abcos(C))

c=sqrt(8^2+5^2-2(8)(5)cos((5pi)/8))

c approx 10.937

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