How do you put #x^2-2x+2y^2-12y+3=0# in standard form, find the center, the endpoints, vertices, the foci and eccentricity?
1 Answer
Feb 3, 2018
Given:
Now,
The given equation becomes
Simplifying
Dividing throughout by 16, we have
Here,
the major axis is
the minor axis is
Centre is
End points:
Eccentricity is