A container has a volume of $4 L$ $4 L$ and holds $2 m o l$ $2 mol$ of gas. If the container is expanded such that its new volume is $5 L$ $5 L$ , how many moles of gas must be injected into the container to maintain a constant temperature and pressure?

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Answer 1 · 2018-02-08T17:22:31

The number of moles is $= 0.5 m o l$ $=0.5mol$

Apply Avogadro's Law :

$\frac{Volume}{Number of moles} = Constant$ $"Volume"/"Number of moles" = "Constant"$

at $Constant Temperature and Pressure$ $"Constant Temperature and Pressure"$

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$ $V_1/n_1=V_2/n_2$

The initial volume is $= 4 L$ $=4L$

The initial number of moles is $n_{1} = 2 m o l$ $n_1=2 mol$

The final volume is $V_{2} = 5 L$ $V_2=5L$

The final number of moles is

$n_{2} = \frac{V_{2}}{V_{1}} \cdot n_{1} = \frac{5}{4} \cdot 2 = 2.5 m o l$ $n_2=V_2/V_1*n_1=5/4*2=2.5mol$

The number of moles to be added is

$n = n_{2} - n_{1} = 2.5 - 2 = 0.5 m o l$ $n=n_2-n_1=2.5-2=0.5mol$

A container has a volume of 4L4 L and holds 2mol2 mol of gas. If the container is expanded such that its new volume is 5L5 L, how many moles of gas must be injected into the container to maintain a constant temperature and pressure?