Question #8dae1
1 Answer
Feb 23, 2018
Apply trig identity:
sin (a + b) = sin a.cos b + sin b.cos a.
In this case:
sin 2x = sin (x + x) = sin x.cos x + sin x.cos x = 2sin x.cos x
Apply trig identity:
sin (a + b) = sin a.cos b + sin b.cos a.
In this case:
sin 2x = sin (x + x) = sin x.cos x + sin x.cos x = 2sin x.cos x