How do you solve the triangle given $△ R S T, r = 38, s = 28, t = 18$ $triangleRST, r=38, s=28, t=18$ ?

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How do you solve the triangle given $△ R S T, r = 38, s = 28, t = 18$ $triangleRST, r=38, s=28, t=18$ ?

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Answer 1 · 2018-02-26T09:52:22

$ˆ R = {109.47}^{\circ}, ˆ S = 44^{\circ}, ˆ T = {26.53}^{\circ}$ $color(brown)(hat R = 109.47^@, hat S = 44^@, hat T = 26.53^@$

Explanation:

$r = 38, s = 28, t = 18$ $color(blue)(r = 38, s = 28, t = 18$

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Given three sides.

$A_{t} = \sqrt{p (p - r) (p - s) (p - t)}$ $A_t = sqrt (p (p-r) (p-s) (p - t))$ where a,b,c are the three sides and p the semi perimeter of the triangle.

$p = \frac{r + s + t}{2} = \frac{38 + 28 + 18}{2} = 42$ $p= (r + s + t) / 2 =(38 + 28 + 18) / 2 = 42$

$A_{t} = \sqrt{42 (42 - 38) (42 - 28) (42 - 18)} = 237.59$ $A_t = sqrt(42 (42-38) (42 - 28) (42 - 18)) = 237.59$

Having known the area, we can find one angle using area formula

$A_{t} = (\frac{1}{2}) r s sin T$ $A_t = (1/2) r s sin T$

$sin T = \frac{237.59 \cdot 2}{38 \cdot 28} = 0.4466$ $sin T = (237.59 * 2) / (38 * 28) = 0.4466$

$ˆ T = {sin}^{- 1} 0 . 4466 = {26.53}^{\circ}$ $hat T = sin ^-1 0. 4466 = 26.53^@$

Similarly, $ˆ S = {sin}^{- 1} (\frac{237.59 \cdot 2}{38 \cdot 18}) = 44^{\circ}$ $hat S = sin ^-1 ((237.59 * 2)/ (38 * 18)) = 44^@$

$ˆ R = 180 - 26.53 - 44 = {109.47}^{\circ}$ $hat R = 180 - 26.53 - 44 = 109.47^@$

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How do you solve the triangle given $△ R S T, r = 38, s = 28, t = 18$ $triangleRST, r=38, s=28, t=18$ ?

1 Answer

Explanation:

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How do you solve the triangle given △RST,r=38,s=28,t=18triangleRST, r=38, s=28, t=18?

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How do you solve the triangle given $△ R S T, r = 38, s = 28, t = 18$ $triangleRST, r=38, s=28, t=18$ ?