how do you add #2\frac { 1} { 2} + 2\frac { 2} { 3}#?

1 Answer

See below.

Explanation:

First, the numbers must be changed to an improper fraction, meaning that there are no whole numbers. I am going to demonstrate how to do this with the #2 1/2#.

Step 1: To start off, you must multiply the denominater

#2 1/color(red)2#

by the whole number

#color(blue)2 1/color(red)2#

to get the equation #color(blue)2*color(red)2#, which equals #4#.

Step 2: Now, you must add the number we just got

#color(green)4#

to the numerator

#2 color(teal)1/2#

getting the equation #color(green)4+color(teal)1#, which equals #5#. Now that 5, becomes our numerator, but the denominater stays the same, which leaves us with the improper fraction of #5/2#.

You can now do the same thing with the other fraction, resulting in the equation #5/2+8/3#.

The next step to solve this problem is to change the denominators so that they are common, or the same number. The first common number they have, is #6#, since #2*3=6# and #3*2=6#.

Since 2 (the denominater) has to be multiplied by 3 to get to 6, 5 (the numerator) must also be multiplied by 3.

#(5*3)/ (2*3)#

This results in the fraction of #15/6#.

Now, in the other fraction, since 3 (denominater) must be multiplied by 2 to get 6, 8 (the numerator) must also be multiplied by 2.

#(8*2)/(3*2)#

This results in the fraction of #16/6#.

Now that the denominaters are the same, the numerators must be added to complete the problem.

#15+16=31#

That is your new numerator, which is put over the common denominater of 6, to get #31/6#.