How do you calculate the derivative for $h(t) = t^3 + 2e^t$ ?

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Answer 1 · 2018-03-02T08:57:02

$h´(t)=3t^2+2e^t$

Because:

A constant is "neutral" for derivative (linearity)

the derivative of $x^n$ is $n·x^(n-1)$

And The derivative of $e^x$ is itself, $e^x$

How do you calculate the derivative for h(t) = t^3 + 2e^th(t) = t^3 + 2e^t?