Question

How do you determine which is greater `(8^2)^2 (<=>) (8^2)^3`?

Answer 1

`(8^2)^3`

Explanation:

Let `x=(8^2)^2`.

We have:

`(8^2)^3`

`=(8^2)^2*8^2`

`=x*8^2`

`=64x`

Since `64>1`, we have `64x>x`, or `(8^2)^3>(8^2)^2`.