A container with a volume of #6 L# contains a gas with a temperature of #560^o K#. If the temperature of the gas changes to #480 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2018-03-02T15:14:29

The new volume is #=5.14L#

Apply Charles' Law

#"Volume"/"Temperature"="Constant"#, at #"Constant Pressure"#

#V_1/T_1=V_2/T_2#

The initial temperature is #T_1=560K#

The final temperature is #T_2=480K#

The initial tvolume is #V_1=6L#

The final volume is

#V_2=T_2/T_1*V_1=(480)/(560)*6=5.14L#