How do you solve #x^2 = x + 6#?
1 Answer
Mar 2, 2018
Explanation:
#"rearrange into standard form"#
#rArrx^2-x-6=0larrcolor(blue)"in standard form"#
#"the factors of - 6 which sum to - 1 are - 3 and + 2"#
#rArr(x-3)(x+2)=0#
#"equate each factor to zero and solve for x"#
#x+2=0rArrx=-2#
#x-3=0rArrx=3#
