How do you differentiate 4/cosx + 1/ tanx? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer maira ยท Monzur R. Mar 3, 2018 d/dx(4secx + cotx)= 4secxtanx - csc^2x Explanation: y=4/cosx+1/tanx dy/dx= d/dx(4secx + cotx) = 4secxtanx - csc^2x Answer link Related questions What is the derivative of y=cos(x) ? What is the derivative of y=tan(x) ? How do you find the 108th derivative of y=cos(x) ? How do you find the derivative of y=cos(x) from first principle? How do you find the derivative of y=cos(x^2) ? How do you find the derivative of y=e^x cos(x) ? How do you find the derivative of y=x^cos(x)? How do you find the second derivative of y=cos(x^2) ? How do you find the 50th derivative of y=cos(x) ? How do you find the derivative of y=cos(x^2) ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 7202 views around the world You can reuse this answer Creative Commons License
