How do you write the expression #6# using exponents? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer MathFact-orials.blogspot.com Mar 4, 2018 See below: Explanation: Here's a few ways: #6=4+2=2^2+2^1# #6=600/100=(25xx24)/(25xx4)=(5^2xx2^3xx3)/(5^2xx2^2)# #6=9-3=3^2-3^1# Answer link Related questions How do you simplify #c^3v^9c^-1c^0#? How do you simplify #(- 1/5)^-2 + (-2)^-2#? How do you simplify #(4^6)^2 #? How do you simplify #3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 #? How do you simplify #4^3ยท4^5#? How do you simplify #(5^-2)^-3#? How do you simplify and write #(-5.3)^0# with positive exponents? How do you factor #12j^2k - 36j^6k^6 + 12j^2#? How do you simplify the expression #2^5/(2^3 times 2^8)#? When can I add exponents? See all questions in Exponents Impact of this question 1599 views around the world You can reuse this answer Creative Commons License