What is the equation of the line that goes through #(2, -5)# and #(-1,-1)#?

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Answer 1 · 2018-03-04T07:48:40

#4x+3y=-7#

Standard form: #Ax+By=C#

First, find the slope of the equation:
#m=[(-5)-(-1)]/[2-(-1)]#

#=-4/3#

Now suppose there is a point #(x,y)# on the line.

#m=(-1-y)/(-1-x)#

#4/-3=(1+y)/(1+x)#

#4+4x=-3-3y#

#4x+3y=-7#