What is the value of #b^2-4ac# for the following equation: #2x^2+3x=-1#?

1 Answer
Jim G.
Mar 4, 2018

#b^2-4ac=1#

Explanation:

#"for a quadratic equation in "color(blue)"standard form"#

#•color(white)(x)ax^2+bx+c=0color(white)(x);a!=0#

#"then the "color(blue) "discriminant "Delta=b^2-4ac#

#"rearrange "2x^2+3x=-1" into standard form"#

#rArr2x^2+3x+1=0larrcolor(blue)"in standard form"#

#"with "a=2,b=3" and "c=1#

#rArrb^2-4ac#

#=3^2-(4xx2xx1)=9-8=1#

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