How do you solve #15t+4=49#?

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Answer 1 · 2018-03-04T10:39:58

#t=3#

Begin by subtracting four from both sides:

#15t+cancel(4-4)=49-4#

#15t=45#

Now we divide both sides by #15# to isolate #t#:

#(cancel15t)/cancel15=45/15#

#t=3#

Answer 2 · 2018-03-04T10:41:48

#t=3#

To solve an equation, we always want the #x# or #t# on its own. Therefore we #-4# from both sides to cancel out the #+4# on the side with #t#.

#15t+4=49 -> 15t=45#

as #49-4=45#, it changes to #45#

Now to solve an equation like this we divide the value, by how much of the #x#, #t# or another unknown value.

#therefore# #t=45/15=3#