Question

How do you solve `3x^2=48`?

Answer 1

`x=+-4`

Explanation:

We begin by dividing both sides by `3`:

`(cancel3x^2)/cancel3=48/3`

`x^2=16`

Take the square root on both sides (and don't forget the negative root):

`sqrt(x^2)=+-sqrt(16)`

`x=+-4`