#f(x) = int (e^(3x)-e^(2x)+x)dx#
#f(x)= inte^(3x)dx - inte^(2x)dx + intxdx#
#f(x)=1/3e^(3x)-1/2e^(2x)+1/2x^2 + C# ; where C#\equiv#constant
#f(x)=1/3e^(3x)+1/2 (x^2-e^(2x)) + C#
#f(0) = 1/3e^(3(0))-1/2e^(2(0))+cancel(1/2(0)^2) + C = -2#
#1/3e^(0)-1/2e^(0)+ C = -2#
#1/3(1)-1/2(1)+ C = -2#
#1/3 - 1/2 + C = -2#
#2/6 - 3/6 + C = -12/6#
# - 1/6 + C = -12/6#
#C = -11/6#
Hence:
#f(x)=1/3e^(3x)+1/2 (x^2-e^(2x)) -11/6#