How do you graph #y-2x=5#?

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Answer 1 · 2018-03-04T23:24:51

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y - (2 * 0) = 5#

#y - 0 = 5#

#y = 5# or #(0, 5)#

Second Point: For #x = 1#

#y - (2 * 1) = 5#

#y - 2 = 5#

#y - 2 + color(red)(2) = 5 + color(red)(2)#

#y - 0 = 7#

#y = 7# or #(1, 7)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-5)^2-0.08)((x-1)^2+(y-7)^2-0.08)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-2x-5)(x^2+(y-5)^2-0.08)((x-1)^2+(y-7)^2-0.08)=0 [-20, 20, -10, 10]}