Question

How do you find all zeros of `h(t)=t^2-6t+9`?

Answer 1

3, that is the only root of `h(t)`.

Explanation:

`h(t)` is a quadratic in `t` which is :
`h(t)=t^2-6t+9`
to find its zeros we equate the function with 0.
#h(t) = 0 => t^2-6t+9 = 0#

Now by splitting the middle term,
`=>t^2 -3t -3t +9= 0`
`=>t(t-3)-3(t-3) = 0`
`=>(t-3)(t-3) = 0`

Hence the root is 3.