Question

If `7/5 L` of a gas at room temperature exerts a pressure of `30 kPa` on its container, what pressure will the gas exert if the container's volume changes to `13/12 L`?

Answer 1

The new pressure is `=38.77kPa`

Explanation:

Apply Boyle's Law

`"Pressure" xx "Volume" = "Constant"` at, #"Constant Tempertature"#

`P_1V_1=P_2V_2`

The initial pressure is `P_1=30kPa`

The initial volume is `V_1=7/5L`

The final volume is `V_2=13/12L`

The final pressure is

`P_2=V_1/V_2*P_1=(7/5)/(13/12)*30=38.77kPa`