Question

A gas sample occupies volume of 2.5 L at a pressure of 1.5 atm. What would be the volume of gas if its pressure is reduced to 1 atm at the same temperature? Find the Given, UnknownLNDP/LSNF with a solution and answer. Thank you.

Answer 1

`"3.75 L"`.

Explanation:

This is what we're given:

• `V_1`, or initial volume, which is `"2.5 L"`.
• `P_1`, or initial pressure, which is `"1.5 atm"`.
• `P_2`, or final pressure, which is `"1 atm"`.

We have to find `V_2`, or the final volume.
Boyle's law actually relates all four of these variables!:

`P_1V_1 = P_2V_2`

This equation can be rearranged to have only `V_2` on one side:

`V_2 = (P_1V_1)/P_2`

Now, we just need to plug in all of the variables to find `V_2`:

`V_2 = ("1.5 atm × 2.5 L")/"1 atm"`

`V_2 = ("1.5" cancel("atm") × "2.5 L")/("1" cancel("atm"))`
`V_2 = "3.75 L"`