A ball with a mass of $144 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $64 (kg)/s^2$ and was compressed by $8/3 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2018-03-06T07:00:06

The height is $=161.2m$

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The spring constant is $k=64kgs^-2$

The compression is $x=8/3m$

The potential energy in the spring is

$PE=1/2*64*(8/3)^2=227.6J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

The sacceleration due to gravity is $g=9.8ms^-2$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

Mass of the ball is $m=0.144kg$

$PE_(ball)=227.6=0.144*9.8*h$

$h=227.6*1/(0.144*9.8)$

$=161.2m$

The height is $=161.2m$

A ball with a mass of 144 g144 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 64 (kg)/s^264 (kg)/s^2 and was compressed by 8/3 m8/3 m when the ball was released. How high will the ball go?