Question

How do you sketch the graph of `y=2sec3x`?

Answer 1

As below

Explanation:

Standard form of equation is `y = a sec (bx - c) + d`

`y = 2 sec 3x`

`a = 2, b = 3, c = 0, d = 0`

Period `= (2pi) / |b| = (2pi) / 2 = pi`

Phase shift `= c / b = 0`

Phase shift 0 to the right

graph{3 sec (2x) [-10, 10, -5, 5]}