How do you solve #5x+60=0#?

Question

2591 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-07T23:17:49

See a solution process below:

First, subtract #color(red)(60)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#5x + 60 - color(red)(60) = 0 - color(red)(60)#

#5x + 0 = -60#

#5x = -60#

Now, divide each side of the equation by #color(red)(5)# to solve for #x# while keeping the equation balanced:

#(5x)/color(red)(5) = -60/color(red)(5)#

#(color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5)) = -12#

#x = -12#