How do you simplify #-8(1-5x)#?

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Answer 1 · 2018-03-08T04:23:59

#-8 + 40x#

#-8(1-5x)#

#=(-8)(1) + (-8)(-5x)#

#=-8 + 40x#

Answer 2 · 2018-03-08T04:24:18

#-8 + 40x#

The parentheses tell us that we multiply all the terms by the outside factor.

So #-8(1-5x)# is really #-8 xx 1 - (-8 xx 5x)#

NOTICE how I put the "stuff" after the subtraction sign into parentheses. That's because we need to simplify #-8# and #5x# before we subtract it

#-8 - (-40 x)#

#-8 + 40x#