What is the equation of a line that goes through #(4,2)# and #(0,2)#?

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Answer 1 · 2018-03-09T07:07:01

#color(blue)(y = 2#

#A_1 (4,2), A_2 (0,2)#

Equation of a line given two points on the line is

#(y-y_1) / (y_2 - y_1) = (x - x_1) / (x_2 - x_1)#

#(y - 2) / (2 - 2) = (x - 4) / (0 - 4)#

#(y - 2) * (0 - 4) = (cancel(color(red)(2 - 2)))^color(green)(0) * ((x - 4)#

#(y - 2) * -4 = 0#

#-4y + 8 = 0#

#-4y = -8# or #y = (-8) / (-4 )= 2#