How do you write # 3x^0 div y^-3# with positive exponents?

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Answer 1 · 2018-03-09T14:15:03

See a solution process below:

First, rewrite the expression as:

#(3x^0)/y^-3#

Then use this rule for exponents to simplify the #x# term:

#a^color(red)(0) = 1#

#(3x^color(red)(0))/y^-3 => (3 xx 1)/y^-3 => 3/y^-3#

Then use this rule of exponents to eliminate the negative exponent:

#1/x^color(red)(a) = x^color(red)(-a)#

#3/y^color(red)(-3) => 3y^color(red)(- -3) => 3y^3#

Answer 2 · 2018-03-09T15:15:39

#3y^3#

#3x^0-:y^-3#

#:.=3xx1-:y^-3#

#:.=3xx1/(y^-3)#

#:.=3/y^-3#

#:.=3y^3#