How do you find the slope of the line passing through the points A(4, 2) and B(-2, 4)?

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How do you find the slope of the line passing through the points A(4, 2) and B(-2, 4)?

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Answer 1 · 2018-03-09T18:26:19

$slope = - \frac{1}{3}$ $"slope "=-1/3$

Explanation:

$to calculate the slope m use the gradient formula$ $"to calculate the slope m use the "color(blue)"gradient formula"$

$∙ x m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $•color(white)(x)m=(y_2-y_1)/(x_2-x_1)$

$let (x_{1}, y_{1}) = (4, 2) and (x_{2}, y_{2}) = (- 2, 4)$ $"let "(x_1,y_1)=(4,2)" and "(x_2,y_2)=(-2,4)$

$\Rightarrow m = \frac{4 - 2}{- 2 - 4} = \frac{2}{- 6} = - \frac{1}{3}$ $rArrm=(4-2)/(-2-4)=2/(-6)=-1/3$

Answer 2 · 2018-03-09T18:31:35

$m = - \frac{1}{3}$ $m=-1/3$

Explanation:

Given:
$A \equiv (4, 2)$ $A-=(4,2)$
$B \equiv (- 2, 4)$ $B-=(-2,4)$
Slope of the line connecting the two points
$A \equiv (x_{1}, y_{1}) and B \equiv (x_{2}, y_{2}) is given by$ $A-=(x_1,y_1)" and "B-=(x_2,y_2)" is given by"$
$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$
Here, we have
$x_{1} = 4$ $x_1=4$
$y_{1} = 2$ $y_1=2$
$x_{2} = - 2$ $x_2=-2$
$y_{2} = 4$ $y_2=4$
$y_{2} - y_{1} = 4 - 2$ $y_2-y_1=4-2$
$y_{2} - y_{1} = 2$ $y_2-y_1=2$
$x_{2} - x_{1} = - 2 - 4$ $x_2-x_1=-2-4$
$x_{2} - x_{1} = - 6$ $x_2-x_1=-6$
Now,
$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{2}{- 6}$ $m=(y_2-y_1)/(x_2-x_1)=2/-6$
$m = - \frac{1}{3}$ $m=-1/3$

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How do you find the slope of the line passing through the points A(4, 2) and B(-2, 4)?

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