How do you divide (s^2-3s)/(s^2-s-6) div (s-6)/(s+2)s23ss2s6÷s6s+2?

1 Answer
Mar 10, 2018

= ((s^2-3s)/(s^2-s-6))/((s-6)/(s+2)) =s23ss2s6s6s+2

= ((s^2-3s)(s+2))/((s^2-s-6)(s-6)) =(s23s)(s+2)(s2s6)(s6)

= ((s^2-3s)(s+2))/((s-3)(s+2)(s-6))=(s23s)(s+2)(s3)(s+2)(s6)

= ((s^2-3s)cancel((s+2)))/((s-3)cancel((s+2))(s-6))

= ((s^2-3s))/((s-3)(s-6))

= ((s^2-3s))/((s^2-9s+18))