The gas inside of a container exerts #8 Pa# of pressure and is at a temperature of #120 ^o K#. If the pressure in the container changes to #64 Pa# with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2018-03-10T10:27:51

For constant volume and mass we can apply Gay Lussac's law,

i.e #P/T# = constant

So,let the final temperature be #T#

so,we can write, #64/T =c# (where, #c# is a constant)

again, from initial conditions of pressure and temperature we get,

#8/120 =c#

so, #64/T =8/120#

so, #T=960K#