Question

Prove: `e^(i pi)+1=0` "?"

Answer 1

Please see below.

Explanation:

`e^(itheta)` is exponential form of a complex number, which in trigonometric form is written as `costheta+isintheta`. Hence,

`e^(ipi)+1=cospi+isinpi+1`

= `-1+i*0+1`

= `0`