How do you write #1/169# as a negative exponent?

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Answer 1 · 2018-03-10T19:32:09

As a negative exponent, #1/169# is #13^-2#.

Rewrite #169# as #13*13#, then use these exponent rules:

#x^color(red)m*x^color(blue)n=x^(color(red)m+color(blue)n)#

#x^(color(red)-color(red)m)=1/x^color(red)m#

Now here's the actual problem:

# color(white)=1/169 #

# =1/(13*13) #

# =1/(13^color(red)1*13^color(blue)1) #

# =1/(13^(color(red)1+color(blue)1)) #

# =1/(13^color(purple)2) #

# =13^color(purple)(-2) #

Answer 2 · 2018-03-10T19:33:54

#13^-2# = #1/13^2# = #1/169#