How do you evaluate the expression #[(1/3)^-2]^3# using the properties? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Hoat V. Mar 11, 2018 #3^6# Explanation: #[(1/3)^-2]^3# #(1/3)^(-2 *3) = (1/3)^-6 = (1^1/3^1)^-6 = (1^1)^-6 / (3^1)^-6# #= 1^-6 / 3^-6 = (1/1^6) / (1/3^6) = 1*3^6/1 = 3^6 # Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 2403 views around the world You can reuse this answer Creative Commons License