How do you solve #2/3x+3=x-2#?

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Answer 1 · 2018-03-11T21:22:38

#x=15#

First let's get all like-terms on the same sides.
To do so, we can subtract 3 from both sides and subtract #x# from both sides as well.

#2/3x+3-3-x=x-2-3-x#

Simplify:
#2/3x-x=-2-3#

Now we can combine like-terms:
#-1/3x=-5#

In order to isolate #x#, multiply by -3 on both sides:
#-3*-1/3x=-5*-3#

Simplify:
#x=15#

Answer 2 · 2018-03-11T21:24:13

#x=15#

So the first thing you would want to do is to move the #2/3x# over to the right side of the equation, making it #-2/3x#.

Subtract #x-2/3x#. Since the is no coefficient, #x# means #3/3x, so

#x-2/3x = 1/3x#

Now move the whole number #-2# to the left side, making it

#3 + 2 = 5#

Multiply both sides by #3# to get #x# alone.

#x=15#