Question

You used 1.01 g of solid and it required 15.00 ml of 1.00 M HCL to reach the endpoint. determine the no of moles of hcl in your titration?

Answer 1

You must have seen the expression..`"concentration"="moles of solute"/"volume of solution"`

Explanation:

And given the quotient....we use....

`"moles of solute"="concentration"xx"volume of solution"`

And so ................

`n_"HCl"=15.00*mLxx10^-3*L*mL^-1xx1.00*mol*L^-1=0.0150*mol`

....and thus the `1.01*g` mass represents this molar equivalence....