How do you solve #\frac { 6n } { 4} + 2= - 16#?

1 Answer
Mar 12, 2018

#n=-12#

Explanation:

#"multiply all terms on both sides of the equation by 4 "#
#"to eliminate the fraction"#

#cancel(4)xx(6n)/cancel(4)+(4xx2)=(4xx-16)#

#rArr6n+8=-64#

#"subtract 8 from both sides"#

#6ncancel(+8)cancel(-8)=-64-8#

#rArr6n=-72#

#"divide both sides by 6"#

#(cancel(6) n)/cancel(6)=(-72)/6#

#rArrn=-12#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#"left "=(-72)/4+2=-18+2=-16=" right side"#

#rArrn=-12" is the solution"#