How do you find the value of the discriminant and determine the nature of the roots #2 x^2 - 3x +1=0#?

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Answer 1 · 2018-03-13T11:30:49

Solution: # x=1 and x= 1/2#

# 2x^2-3x+1=0#

Comparing with standard quadratic equation #ax^2+bx+c=0#

# a=2 ,b=-3 ,c=1# Discriminant, # D= b^2-4ac# or

#D=9 - 8 =1#. If discriminant positive, we get two real solutions,

if it is zero we get just one solution, and if it is negative we get

complex roots. Discriminant is positive here , so it has two

distinct root . Quadratic formula: #x= (-b+-sqrtD)/(2a) #or

#x= (3+-sqrt1)/4 :. x= (3+-1)/4 :. x=1 and x= 1/2#

Solution: # x=1 and x= 1/2# [Ans]