How do you factor the expression #7x^2 - 28 =0#?

1 Answer
Carl S.
Mar 13, 2018

#7(x^2 -4)=0#

Explanation:

Both 7 and 28 are divisible by 7 so factorizing this you would get:
#7(x^2 -4)=0#

After factorizing you can then proceed to solve the equation.

Dividing both sides by 7 we get #x^2 -4=0# (the right hand side remains unchanged.)

We can move the 4 to the right hand side to get:
#x^2 =4#
The answer is thus #x=±2#

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