How do you solve #4/9 = r - 3 / 6#?

1 Answer
Mar 14, 2018

#r=17/18#

Explanation:

#"multiply all terms by the "color(blue)"lowest common multiple"#
#"of 9 and 6 which is 18"#

#cancel(18)^2xx4/cancel(9)^1=18r-(cancel(18)^3xx3/cancel(6)^1)#

#rArr8=18r-9#

#"add 9 to both sides"#

#8+9=18rcancel(-9)cancel(+9)#

#rArr18r=17#

#"divide both sides by 18"#

#(cancel(18) r)/cancel(18)=17/18#

#rArrr=17/18#

#color(blue)"As a check"#

Substitute this value into the right side of the equation and if equal to the left side then it is the solution.

#"right side "=17/18-9/18=8/18=4/9=" left side"#

#rArrr=17/18" is the solution"#