How do you solve #13s + - 11s - (- 18)= 6#?

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Answer 1 · 2018-03-14T20:51:46

Combine like-terms and get #s# by itself.
The final answer is #s=-6#

1) distribute the negative into the parenthesis #(-18)#

#13s+ - 11s - - 18 = 6#

2) Change the 'double negative' to a positive.

#13s+ - 11s +18 = 6#

3) Combine 'like term', which means you can add #13s# and #-11s#.

#2s + 18 = 6#

4) subtract #18# from both sides, in order to get the variable #s# by itself.

#2s + 18 - 18= 6 - 18#

#2s = -12#

5) divide each side by 2, in order to solve for #s#.

#(2s)/2 = (-12)/2#

#s=-6# <-- final answer