How do you solve #6(2x – 3) = 30#?

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Answer 1 · 2018-03-15T01:17:49

#x = 4#

Start:

#6(2x-3)=30#

Distribute the 6:

#12x - 18 = 30#

Add 18 to both sides:

#12x = 48#

Divide both sides by 12:

#x = 4#

Answer 2 · 2018-03-15T01:27:22

The answer is x = 4

First you distribute the 6 to all the terms
inside the parenthesis.
This makes the equation look like this:

#12x-18=30#

Then you isolate the x variable by shifting
all constants to the other side.
The equation would look like this:

#12x=30+18#

Now you just simplify the problem and
then divide the variable by the coefficient.

#12x=48#

#(12x)/12=48#

#x=4#